That said, there is no need to do such things now with findLast and findLastIndex methods. So obviously there is no way to search for an array item using a condition starting from the right side of the array and this is what these two new methods are bringing to the table. These two methods search starting from the left side and they stop when they find a match. JavaScript currently supports () and () to find the index of an item in the array.Īpart from these, we can use () and () to spot an element in the array based on some condition. The space complexity is O(1), as no additional data structures are used in the solution.At the moment of this writing two brand-new array methods named findLast and findLastIndex are getting closer to official release since they are in stage 3. The time complexity of this solution is O(1), as the calculation of the final position and the retrieval of the element at that position are both constant-time operations. To optimize this solution, you can use the modulo operator to keep the calculated position within the bounds of the array, so you don't need to check for negative values. Return the element at the calculated position in the array. The approach for finding the mth element after k right rotations of an array can be broken down as follows −Ĭalculate the actual position of the mth element after k rotations, which would be (m-k) % n, where n is the length of the array.Ĭheck if the calculated position is negative, in which case it can be converted to a positive position by adding n to it. Finally, we will return the mth element of the rotated array as the result.
We will continue this loop for k times to get the rotated array. In each iteration of the loop, we will move the last element of the array to the first position.
Then, we will use a loop to perform the right rotations. Firstly, we will take the input for the array, m and k.
We are writing a JavaScript program to find the mth element after k right rotations of an array.
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